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Oracle Introduction to Oracle9i: SQL Sample Questions:
1. Management has asked you to calculate the value 12*salary* commission_pct for all the employees in the EMP table. The EMP table contains these columns:
Which statement ensures that a value is displayed in the calculated columns for all employees?
A) SELECT last_name, 12*salary*(decode(commission_pct,0)) FROM emp;
B) SELECT last_name, 12*salary* (commission_pct,0) FROM emp;
C) SELECT last_name, 12*salary*(nvl(commission_pct,0)) FROM emp;
D) SELECT last_name, 12*salary* commission_pct FROM emp;
2. Examine the structure of the EMPLOYEES table:
EMPLOYEE_ID NUMBER Primary Key
FIRST_NAME VARCHAR2(25)
LAST_NAME VARCHAR2(25)
Which three statements insert a row into the table? (Choose three.)
A) INSERT INTO employees (employee_id, first_name, last_name) VALUES ( 1000, 'John', ' ');
B) INSERT INTO employees (employee_id) VALUES (1000);
C) INSERT INTO employees (first_name, last_name, employee_id) VALUES ( 1000, 'John', 'Smith');
D) INSERT INTO employees VALUES ( NULL, 'John', 'Smith');
E) INSERT INTO employees( first_name, last_name) VALUES( 'John', 'Smith');
F) INSERT INTO employees VALUES ( 1000, 'John', NULL);
3. You need to display the last names of those employees who have the letter "A" as the second character in their names.
Which SQL statement displays the required results?
A) SELECT last_name FROM EMP WHERE last_name LIKE '_A%';
B) SELECT last_name FROM EMP WHERE last name ='*A%'
C) SELECT last_name FROM EMP WHERE last name ='_A%';
D) SELECT last_name FROM EMP WHERE last name LIKE '*A%'
4. You need to produce a report for mailing labels for all customers. The mailing label must have only the customer name and address. The CUSTOMERS table has these columns:
Which SELECT statement accomplishes this task?
A) SELECT name, address FROM customers;
B) SELECT id, name, address, phone FROM customers;
C) SELECT* FROM customers;
D) SELECT cust_id, cust_name, cust_address, cust_phone FROM customers;
E) SELECT cust_name, cust_address FROM customers;
5. Examine the data from the EMP table:
The COMMISSION column shows the monthly commission earned by the employee.
Which three tasks would require subqueries or joins in order to perform in a single step? (Choose three)
A) Decreasing the commission by 150 for the employees who are working in department 30 and earning a commission of more then 800.
B) Increasing the commission of employee 3 by the average commission earned in department 20.
C) Inserting into the table a new employee 10 who works for department 20 and earns a commission that is equal to the commission earned by employee 3.
D) Creating a table called COMMISSION that has the same structure and data as the columns EMP_ID and COMMISSIONS of the EMP table.
E) Finding the number of employees who do NOT earn commission and are working for department 20.
F) Deleting the records of employees who do not earn commission.
Solutions:
Question # 1 Answer: C | Question # 2 Answer: A,B,F | Question # 3 Answer: A | Question # 4 Answer: E | Question # 5 Answer: B,C,D |